AMBOY – The Mendota girls’ basketball teams will compete in the Amboy Holiday Tournament set for Dec. 26-29. There are six teams in the varsity tournament and four teams in the freshman-sophomore tournament.

The varsity squad is in the Red Pool along with Newman and Hiawatha. The Black Pool consists of Amboy, Hall and Somonauk.

Teams in the freshman-sophomore pool are Amboy, Mendota, Somonauk and Hall. They will play a round robin format.

The pairings are as follows:

Amboy Girls’ Holiday Tournament

Tuesday, Dec. 26

Noon – Mendota vs. Hall (FS)

1:30 p.m. – Amboy FS vs. Somonauk (FS)

3 p.m. – Hall vs. Somonauk (V)

4:30 p.m. – Newman vs. Hiawatha (V)

6 p.m. – Amboy vs. Mendota (V)

Wednesday, Dec. 27

Noon – Mendota vs. Somonauk (FS)

1:30 p.m. – Amboy vs. Hall (FS)

3 p.m. Hiawatha vs. Mendota (V)

4:30 p.m. – Newman vs. Somonauk (V)

6 p.m. – Amboy vs. Hall (V)

Thursday, Dec. 28

Noon – Amboy vs. Mendota (FS)

1:30 p.m. – Hall vs. Somonauk (FS)

3 p.m. – Hiawatha vs. Hall (V)

4:30 p.m. – Newman vs. Mendota (V)

6 p.m. – Amboy vs. Somonauk (V)

Friday, Dec. 29

3 p.m. – Red Pool #3 vs. Black Pool #3

4:30 p.m. – Red Pool #2 vs. Black Pool #2

6 p.m. – Red Pool #1 vs. Black Pool #1